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    English: A geostationary orbit can only be achieved at an altitude very close to 35,786 km (22,236 mi), and directly above the equator. This equates to an orbital velocity of 3.07 km/s (1.91 mi/s) or a period of 1,436 minutes, which equates to almost exactly one sidereal day or 23.934461223 hours. This makes sense considering that the satellite must be locked to the Earth's rotational period in order to have a stationary footprint on the ground. In practice, this means that all geostationary satellites have to exist on this ring
    http://weelookang.blogspot.com/2010/07/ejs-open-source-geostationary-satellite.html
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    Author Lookang many thanks to author of original simulation = Francisco Esquembre author of Easy Java Simulation = Francisco Esquembre
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    27 June 2011

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    Date/TimeThumbnailDimensionsUserComment
    current05:04, 12 June 2013Thumbnail for version as of 05:04, 12 June 2013220 × 220 (111 KB)Lookangupdated earth texture with public domain better resolution
    05:02, 12 June 2013Thumbnail for version as of 05:02, 12 June 2013220 × 220 (420 KB)Lookangupdated with public domain earth texture. radius of earth is proportional to geostationary orbit now
    01:29, 27 June 2011Thumbnail for version as of 01:29, 27 June 2011220 × 220 (420 KB)Lookang

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