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Normal extension

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In abstract algebra, a normal extension is an algebraic field extension L/K for which every irreducible polynomial over K that has a root in L splits into linear factors over L.[1][2] This is one of the conditions for an algebraic extension to be a Galois extension. Bourbaki calls such an extension a quasi-Galois extension. For finite extensions, a normal extension is identical to a splitting field.

Definition

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Let L/K be an algebraic extension (i.e., L is an algebraic extension of K), such that L⊆K‾ (i.e., L is contained in an algebraic closure of K). Then the following conditions, any of which can be regarded as a definition of normal extension, are equivalent:[3]

  • Every embedding of L in K‾ over K induces an automorphism of L.
  • L is the splitting field of a family of polynomials in K[X].
  • Every irreducible polynomial of K[X] that has a root in L splits into linear factors in L.

Other properties

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Let L be an extension of a field K. Then:

  • If L is a normal extension of K and if E is an intermediate extension (that is, L ⊇ E ⊇ K), then L is a normal extension of E.[4]
  • If E and F are normal extensions of K contained in L, then the compositum EF and E ∩ F are also normal extensions of K.[4]

Equivalent conditions for normality

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Let L/K be algebraic. The field L is a normal extension if and only if any of the equivalent conditions below hold.

  • The minimal polynomial over K of every element in L splits in L;
  • There is a set S⊆K[x] of polynomials that each splits over L, such that if K⊆F⊊L are fields, then S has a polynomial that does not split in F;
  • All homomorphisms L→K¯ that fix all elements of K have the same image;
  • The group of automorphisms, Aut(L/K), of L that fix all elements of K, acts transitively on the set of homomorphisms L→K¯ that fix all elements of K.

Examples and counterexamples

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For example, ℚ(2) is a normal extension of ℚ, since it is a splitting field of x2−2. On the other hand, ℚ(23) is not a normal extension of ℚ since the irreducible polynomial x3−2 has one root in it (namely, 23), but not all of them (it does not have the non-real cubic roots of 2). Recall that the field ℚ‾ of algebraic numbers is the algebraic closure of ℚ, and thus it contains ℚ(23). Let ω be a primitive cubic root of unity. Then since, ℚ(23)={a+b23+c43∈ℚ‾|a,b,c∈ℚ} the map {σ:ℚ(23)⟶ℚ‾a+b23+c43⟼a+bω23+cω243 is an embedding of ℚ(23) in ℚ‾ whose restriction to ℚ is the identity. However, σ is not an automorphism of ℚ(23).

For any prime p, the extension ℚ(2p,ζp) is normal of degree p(p−1). It is a splitting field of xp−2. Here ζp denotes any pth primitive root of unity. The field ℚ(23,ζ3) is the normal closure (see below) of ℚ(23).

Normal closure

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If K is a field and L is an algebraic extension of K, then there is some algebraic extension M of L such that M is a normal extension of K. Furthermore, up to isomorphism there is only one such extension that is minimal, that is, the only subfield of M that contains L and that is a normal extension of K is M itself. This extension is called the normal closure of the extension L of K.

If L is a finite extension of K, then its normal closure is also a finite extension.

See also

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Citations

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  1. ↑ Lang 2002, p. 237, Theorem 3.3, NOR 3.
  2. ↑ Jacobson 1989, p. 489, Section 8.7.
  3. ↑ Lang 2002, p. 237, Theorem 3.3.
  4. 1 2 Lang 2002, p. 238, Theorem 3.4.

References

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  • Lang, Serge (2002), Algebra, Graduate Texts in Mathematics, vol. 211 (Revised third ed.), New York: Springer-Verlag, ISBN 978-0-387-95385-4, MR 1878556
  • Jacobson, Nathan (1989), Basic Algebra II (2nd ed.), W. H. Freeman, ISBN 0-7167-1933-9, MR 1009787